Question

if the speed of light inside a diamond were 0.42 times of that in air. what will be it's refractive index.

Answer 1

Refractive Index N= n/. 42n= 2.380952380952380

Answer 2

Answer:

The value of the refractive index is 2.4 .

Step-by-step explanation:

The formula for refractive index is given by.

$n =\frac{c}{v}$

Where c is the speed of light in air , v is the speed of light in medium.

As given

if the speed of light inside a diamond were 0.42 times of that in air.

As

$Speed\ of\ light\ in\ air = 3.0\times 10^{8}\ m/s$

Speed of light in diamond = 0.42 × Speed of light in air

$Speed\ of\ light\ in\ diamond= 0.42\times 3.0\times 10^{8}\ m/s$

$Speed\ of\ light\ in\ diamond= 1.26\times 10^{8}\ m/s$

Now values in the formula

$n =\frac{3.0\times 10^{8}}{1.26\times 10^{8}}$

n = 2.4(Approx)

Therefore the value of the refractive index is 2.4.