Question

If the speed of light is 3.0*10 to the power 8 ms, calculate the distance covered by lights in 2.00 NS give detail explanation.

Answer 1

Distance covered = speed × time
                             = 3×10^8 × 2.0NS
                             = 3×10^8 × 2.0×10^-9
                             = 0.6m

Answer 2

Distance covered = Speed×Time = 3.0 × 108ms-1 × 2.00 ns
= 3.0×108ms-1×2.00 ns×10-9s/1ns = 6.00×10-1m = 0.600m