Chemistry, asked by nice61, 1 year ago

if the speed of light is 3.0 into 10 to the power 8 metre per second calculate the distance covered by light in 2 NS

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Answered by aqibkincsem
16

1 mm=10^-6 km 1pm=10^-15 km 1NS=10^-9 second separation = speed × time:- distance= 3×10^8×2×10^-9:- distance=6×10^-1 meter.

The speed of light in vacuum, normally signified c, is an all inclusive physical consistent critical in numerous zones of material science.

Its correct esteem is 299,792,458 meters for each second. Physicists frequently utilize the letter c to mean the speed of light in void space (vacuum).

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