Question

If the speed of light is $3.0 \times 10^{8} ms^{-1}$, calculate the distance covered by light in 2.00 ns.

Answer 1

According to the question:

Time taken to cover the distance = 2.00 ns

                     $= 2.00\quad \times \quad { 10 }^{ -9 }\quad s$

Speed of light $=\quad 3.0\quad \times \quad { 10 }^{ 8 }\quad m/s$

We know, Speed $=\quad \frac { Distance }{ Time }$

Or  

Distance $=\quad Speed\quad \times \quad Time$

Therefore, Distance travelled by light in 2.00 ns $= Speed \quad of\quad light \times Time\quad taken$

                     $=\left( 3.0\times { 10 }^{ 8 }m/s \right) \left( 2.00\times { 10 }^{ -9 }s \right)$

                     $=6.00\times { 10 }^{ -1 }m$

                     $Distance = 0.600m$

Answer 2

Hey mate......

the distance is= 0.600m☺✌☺