If the square of a hypotunes of an isosceles right triangle is 128 cm2 find the length of each side
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let ABC be triangle
AB=AC eq.1
BC is hypotenuse
so AB2+AC2=BC2
from eq.1
AB2+AB2=128
2AB2=128
AB2=64
AB=ROOT64
AB=8cm
so sides other than hypotenuse are of 8cm
AB=AC eq.1
BC is hypotenuse
so AB2+AC2=BC2
from eq.1
AB2+AB2=128
2AB2=128
AB2=64
AB=ROOT64
AB=8cm
so sides other than hypotenuse are of 8cm
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