Question

If the square of the hypotenuse of an isosceles right angle is 98 sq cm find the length of each side.

[remember hypotenuse is 98 sq cm ]

l asked this question twicr, but everyone is writing only 98 of 98 sq. Why?

Please answer correct. It is very urgent. Tomorrow will be my exam.​

Answer 1

Answer:

Let ABC be the given isosceles right triangle such that <B = 90° , side AC is the hypotenuse; and, AB= BC

Then, (AB)^2 + (BC)^2 = (AC)^2…. Pythagoras theorem.

(AC)^2 = 98 sq. cm. ( given)

So, (AB)^2 + ((BC)^2 = 98

But, AB = BC = a ( say) …. ( given)

Therefore, a^2 + a^2 = 98

Or, 2a^2 = 98.

So, a^2 = 98 / 2 = 49

Hence, a = AB = BC = √49 = 7 cm.

The side AC ( the hypotenuse) = √98 = √(7 *7*2)

= 7 *√2 = 7* 1.414 = 9..898cm., say, 9.9 cm.

Hence, the three sides of the right isosceles triangle are 7 cm, 7cm and ~ 9.9 cm. Answer

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Answer 2

Answer:

hope so it will helpful to you