Question

If the squared difference of the zeroes of the quadratic
polynomial f x x px 45 2
^ h = + + is equal to 144, find
the value of p.how 4ab comes

Answer 1

Answer:

÷18

Step-by-step explanation:

x² + px + 45 = 0

a = 1 ; b = p ; c = 45

Let α and β be the roots of the equation.

α + β = -b/a = -p/1 = -p

αβ = c/a = 45

(α - β)² = (α + β)² - 4αβ

144 = (-p)² - 4 * 45

p² = 144 + 180 = 324

p = ± 18.