if the squared difference of the zeros of quadratic polynomial P(x) = x²+ 3x + k is 3, find k
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If A and B are the zeros of the polynomial f(x)=x2-5x+k such that alpha minus beta =1, what is the value of k?
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x2-5x+k
Here, a=1, b=-5 and c=k
Now, alpha+beta= -b/a= -(-5)/1= 5
alpha*beta= c/a= k/1= k
Now, apha-beta=1
Squaring both sides, we get,
(alpha-beta)2 = (1)2
=> (alpha+beta)2-4*aplha*beta=1
=> (5)2-4k=1
=> -4k= 1-25
=> -4k= -24
=> k=6
So the value of k is 6.
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