Math, asked by sampada8340, 11 months ago

If the squared difference of the zeros of the quadratic polynomial f x is equal to x square + bx + 45 is equal to 144 find the value of p

Answers

Answered by DipanshuAgnihotri
0

x ^ px + 45 =0

let rots a and b

Now (a+b)^2-4ab =144

p^2-4*45 =144

p^2=324

p=+18or-18

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