Question

if the squared difference of the zeros of the quadratic polynomial f x is equal to X square + bx + 45 is equal to 144 find the value of b​

Answer 1

hope this will help you mark me as brainlist

Answer 2

Let α,β are the roots of the quadratic polynomial f(x) = x2+px+45 then

α + β = -p ---------(1) and

αβ = 45 Given (α - β)^2 = 144

∴ (α + β)^2 – 4αβ = 144

⇒ (– p)^2 – 4 × 45 = 144 [Using (1)]

⇒ p ^2 – 180 = 144

⇒ p^ 2 = 144 + 180 = 324

Thus, the value of p is ± 18.