Physics, asked by deepika1789, 1 year ago

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a body is thrown up with a velocity 29.23m/s.distance travelled in last second of its journey is...?

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Answers

Answered by ashish17817
2
Distance = speed/time n therefore the dist is 29.23m/s
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Answered by shamitakhanduri
1

u=29.23m/s

v=0 (stops at top)

g=9.8

g=v-u /t

9.8=-29.23/t

now solve it by ur own

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