Question

If the straight line ax+by+p=0 and xcos+ysin=p enclosed an angle of 4 and the line xsinycos=0 meets them at the same point , the a2+b2 is

Answer 1

Answer:

Step-by-step explanation:

Given lines are

L1→ax+by+c=0

L2→xcos(α)+ysin(α)=c

L3→xsin(α)−ycos(α)=0

As given conditions are that above three given lines pass through a fixed point.

L1 does subtend an angle of π4 with L2 and L3 subtend an angle of π2 with L2 because the product of their slope =−L1

Hence L1 is the angle bisector between L2 and L3 . Here the two possible orientation of L1 shows

Now equations of the angle bisectors between L2 and L3

Now follow the diagram for the solving numerical part

Answer 2

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