If the string break at the highest position, what is the horizontal distance travel by the ball
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Horizontal Speed at the time of breaking = v.
Initial speed imparted to the ball at the lowest position = u.
Length of string = L.
Conserving energy:
m u^2/ 2 = m v^2/ 2 + 2 m g L
v^2 = u^2 - 4gL
Height through which the ball dropped = 2L.
Time to hit ground = t.
2L = g t^2 /2 . So. t = 2 * sqrt(L/g).
Horizontal distance traveled = v*t
= 2 sqrt(L/g)* sqrt (u^2 - 4gL).
.
Initial speed imparted to the ball at the lowest position = u.
Length of string = L.
Conserving energy:
m u^2/ 2 = m v^2/ 2 + 2 m g L
v^2 = u^2 - 4gL
Height through which the ball dropped = 2L.
Time to hit ground = t.
2L = g t^2 /2 . So. t = 2 * sqrt(L/g).
Horizontal distance traveled = v*t
= 2 sqrt(L/g)* sqrt (u^2 - 4gL).
.
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