Question

if the sum and product of zeroes of p(x) are a2 and -a1/a3 then find p(x) = ?​

Answer 1

Answer:

Step-by-step explanation:

P(x)=(a+1)x  

2

+(2a+3)x+(3a+4)

Sum of root (s) = -1  

(  

coff.ofx  

2

 

−(coff.ofx)

​  

)

⇒  

a+1

−(2a+3)

​  

=−1

−(2a+3)=−(a+1)

−2=a

Product of roots =  

a+1

3a+4

​  

=  

−2+1

3(−2)+4

​  

=2

(  

coffofn  

2

 

Constant

​  

)

Answer 2

X^2-(sum)X + product =0
Put value
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