If the sum of 3 consecutive
numbers is 48,then the smallest
number is *
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Answered by
17
Answer:
If the sum of 3 consecutive
numbers is 48,then the smallest
number is 15
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Step-by-step explanation:
Let the three consecutive numbers be x, x + 1, and x + 2
Their sum is 48
According to the question,
⟹ x + x + 1 + x + 2 = 48
⟹ 3x + 3 = 48
⟹ 3x = 45
⟹ x = 9
And other numbers will be 10, and 11
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