if the sum of 3rd and 10th terms of an increasing ap is 39 while the difference between their 7th and 11th terms 12 find the second term
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Answered by
0
Answer:
Step-by-step explanation:
a3+a10=39
a+(3-1)d +a+(10-1)d=39
2a+11d=39. (Let equation 1)
a7-a11=12
a+(7-1)d-a-(11-1)d=12
-4d=12
d=-3
Substitute d=-3 in equation 1
2a+11(-3)=39
2a=72
a=36
2nd term is
a2=a+(2-1)d
=36 -3
=33
Answered by
0
Answer:
33
Step-by-step explanation:
a3+a10=39
a1+2d+a1+9d=39
2a1+11d=39
a7-a11=12
a1+6d-(a1+10d)=12
a1+6d-a1-10d=12
-4d=12
d=-3
2a1+11(-3)=39
2a1+(-33)=39
2a1=72
a1=36
a1+d=a2
36-3=a2
33
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