Question

If the sum of 6 terms of an ap is 36and that of the first 16 terms is 256 find the sum of first ten terms

Answer 1

n/2 (2a+(n-1)d=36
where n is 6.


n/2 (2a+(n-1)d=256
whwre n is 16


working out , we get d=2 and a=1

then, n/2(2a+n-1)d=?
where d=2 and a=1 Hope it helps

Answer 2

n/2 (2a+(n-1)d=36
where n is 6.


n/2 (2a+(n-1)d=256
whwre n is 16


working out , we get d=2 and a=1

then, n/2(2a+n-1)d=?
where d=2 and a=1 Hope it helps