Question

If the sum of a quadratic equation 3x2 +(2k+1)x–(k+5) = 0, is equal to the productof the roots, then the value of k is ____

Answer 1

Solution:

Compare given Quadratic equation

3x²+(2k+1)x-(k+5) = 0 with

ax²+bx+c=0, we get

a = 3 , b = (2k+1), c = -(k+5)

i ) Sum of the roots = -b/a

= -(2k+1)/3 ---(1)

ii) product of the roots = c/a

= -(k+5)/3 ----(2)

According to the problem given,

-(2k+1)/3 = -(k+5)/3

=> 2k+1 = k+5

=> 2k-k = 5-1

=> k = 4

Therefore,

k = 4

••••

Answer 2

Step-by-step explanation:

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