Question

if the sum of ages of father and son is 65 years and twice the difference of their ages is 50years, then the age of the father (in years)

Answer 1

let the age of son be y
let the age of father be x
x+y=65
and twice the difference of their age is 50 yrs
2(x+y)=50
2x+2y=50

x+y=65......1
2x-2y=50.......2
by elemination method adding 1 and 2
2(x+y=65)
+
2x-2y=50
therefore 2x+2y=130
2x-2y=50
4x+0=180
x=180÷4
x=45
x+45=65
there fore 20 is son sage and 45 is father age

Answer 2

Answer:

20 son age and 45 father age