If the sum of diameter and height of a cone is 10 cm, what will be radius of the cone when the volume is maximum?
a.3.33 cm
b.5 cm
c.6.66 cm
d.7 cm
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Answer:
condition:
D+h=10
2r+h=10
h=10-2r
volume of cone= (1/3)*πr^ 2h
=(1/3)*πr^2(10-2r)
v=(10/3)*πr^2 -(2/3)*πr^3
dv/dr = (20/3)πr-2πr
when volume is maximum, dv/dr =0
dv/dr =(20/3)πr-2πr=0
(20/3)πr= 2πr
r= 3.33 cm
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