if the sum of first 14 term of an AP is 1050 and its first term is 10 find the 20th term ?
Answers
Answered by
17
Step-by-step explanation:
N/2[2a + (n-1)d] = Sn14
14/2[2×10 + (14-1)d =1050
7 [20 +13d] =1050
20+13d. = 1050/7
13d = 150-20
13d. = 130
d. = 10
So
a = 10
d = 10
T20 = a+ (n-1)d
T20 = 10 + (20-1) 10
T20 = 10 +19×10
T20 = 10 +190
T20 = 200
so the 20th term is 200.
Hope it will help u .
Answered by
1
Answer:
200
step by step explanation:
refer the attachment mate
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