if the sum of first 7 terms of an Ap is 49 and that of 17 terms is 239, find the first n terms
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Sum of n terms=n²
Step-by-step explanation:
if the sum of first 7 terms of an Ap is 49 and that of 17 terms is 289, find the sum of first n terms
S7=49=7/2 ( 2a+6d)
2a+6d=49*2/7=14
2a+6d=14....................(1)
S17=239=17/2( 2a+16d)
2a+16d=289*2/17=17*2=34
2a+16d=34..................(2)
subtract (1) from(2)
10d=20,d=2
from(1)2a+12=14
2a=2,a=1
Sn=n/2( 2*1+(2(n-1) }
=n/2 ( 2+2n-2)
=n/2 ( 2n
=n²
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