if the sum of first 9 terms of an A.P
is 72 and the common difference is 5, find
the first term and the 10th term of the AP
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Step-by-step explanation:
Let the first term be a
9th term = a+8d
S₉ (Sum to nine terms) = 9/2(a+a+8*5)
72 = 9/2(2a+40)
2a + 40 = 16
2a = -24
a = -12
First term = -12
Tenth term = -12+9*5 = 33.
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