Question

If the sum of first m terms of an AP is am²+bm, find its common difference.


Don't post irrevelant answers pls ​

Answer 1

Answer:

2a

Step-by-step explanation:

Sm =am²+bm

let m=1

S1 = a(1)²+bm

S1=a+b

now

A1=a+b (S1=a1)

S2=a(2)²+b(2)

=4a+2b

a2=s2-s1

=4a+2b-(a+b)

=4a+2b-a-b

=3a+b

now the common difference = a2-a1

=3a+b-(a+b)

=3a+b-a-b

=2a