If the sum of first m terms of an AP is
the same as the sum of its first n terms, show
that the sum of its first (m+n) terms is zero
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Answered by
0
Answer: Sm+n = 0. Proof.
Step-by-step explanation:
Sm = Sn
m/2 *( 2a + (n-1)d) = n/2 * (2a +(n-1)d)
m(2a) + m(n-1)d = n(2a) + n(n-1)d) =0
2a(m-n) + d(m^2 - m -n^2 +n) =0
2a(m-n) + d(m^2 -n^2 - m+n) =0
(m-n) (2a + (m+n-1)d) =0
Sm+n = (m+n)/2 * (2a + (m+n-1)d)
(m+n)/2 * 0
= 0
Answered by
1
Step-by-step explanation:
here is your answer and once try to solve it yourself
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