If the sum of first n terms is (3n²+5n),find its common difference.
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Answered by
20
Sn=3n2+5n
S1=3+5=8=a
S2=12+10=22
T2=S2-S1=22-8=14
d=t2-a=14-8=6
I hope its correct.......
S1=3+5=8=a
S2=12+10=22
T2=S2-S1=22-8=14
d=t2-a=14-8=6
I hope its correct.......
hastidDobariya:
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ya thanks it was helpful
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but there no tag of brainliest...
it will come after two answers are given
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Answered by
6
Let the first term be a and the common difference be d.
S1 = a = 3*1+5*1 = 3+5 = 8.
S2 = 3*4+5*2 = 12+10 = 22.
a2 = S2 - S1 =22-8=14.
d=a2-a=14-8=6.
S1 = a = 3*1+5*1 = 3+5 = 8.
S2 = 3*4+5*2 = 12+10 = 22.
a2 = S2 - S1 =22-8=14.
d=a2-a=14-8=6.
thank you
ans sorry hastidobariya already asked for brainliest ...
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