Question

If the sum of first n terms of an ap is given by
$sn = 3 {n}^{2} - 4n$
, then the find its nth term

Answer 1

an=Sn-Sn-1

an=3n^2-4n-3(n-1)^2-4n-1

an=3n^2-4n-3n^2-3+6n-4n+4

an=6n-8n+1

an=1-2n