if the sum of first p term of an ap is (ap²+bp) find its common difference
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Step-by-step explanation:
Given that the sum of p terms of an AP is ap
2
+bp
Now, put p=1,2,3,.....
S
p
=ap
2
+bp
⇒ S
1
=a(1)
2
+b(1)
∴ S
1
=a+b
⇒ S
2
=a(2)
2
+b(2)
∴ S
2
=4a+2b
∴ a
1
=S
1
=a+b
∴ a
2
=S
2
−S
1
=4a+2b−(a+b)
=4a+2b−a−b
=3a+b
∴ Common difference =d
⇒ d=a
2
−a
1
⇒ d=3a+b−(a+b)
⇒ d=3a+b−a−b
∴ d=2a
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