if the sum of first seven terms of an AP is 49 and that of seventeen terms is 289 .find the sum of the first n terms.
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Step-by-step explanation:
S7=7/2(2a+(7-1)d)
49=7(a+3d)
7=a+3d....(1)
S17=17/2(2a+16d)
289=17(a+8d)
17=a+8d.....(2)
on subtracting (1)&(2),we get
5d=10
d=2
putting d=2,in equ. (1),then we get
a=1
sn= n/2 [2a+ (n-1)d]
=n/2[2(n)]
=n2
sn =n2
ashamonikakati2:
ok
Answered by
1
do it further n u will get it's answer
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