Question

If the sum of four numbers in A.P. be 48 and that
the product of the extremes is to the product of
the means is 27 to 35 then the numbers are-
(A) 3, 9, 15, 21 (B) 9, 5, 7,3
(C) 6, 10, 14, 18 (D) None of these

plz give answer with method
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Answer 1

Answer : (C) 6, 10, 14, 18

Step by step explanation :

Let's take the four numbers as (a-3d),(a-d),(a+d),(a+3d)

Common difference be 2d.

Now,

Sum of four numbers = 48

.°. (a-3d)+(a-d)+(a+d)+(a+3d) = 48

4a = 48

a = 12...(1)

Now, Product of means/Product of Extremes = 35/27

.°. (a-d)(a+d) / (a-3d)(a+3d) = 35/27

a^2 - d^2 / a^2 -9d^2 = 35/27 ...(2)

From (1) and (2),

We get :

d = 2

So the four numbers are:

a - 3d = 12 - 3*2 = 6

a - d = 12 - 2 = 10

a + d = 12 + 2 = 14

a + 3d = 12 + 6 = 18

=> 6, 10, 14, 18

Answer : Opt. C) 6, 10, 14, 18

Answer 2

Step-by-step explanation:

here is ur ans