If the sum of lcm and hcf of 2 numbers is 1260,there lcm is 900 more than there hcf then find the product of 2 numbers
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Answered by
1
lcm + hcf= 1260
lcm= 1260 - hcf
lcm= hcf+ 900
1260-hcf = hcf + 900
1260- 900= hcf + hcf
360 = 2× hcf
hcf= 360/2
hcf= 180
lcm = 180+ 900
lcm= 1080
product of 2 no. = lcm× hcf
= 1080×180
lcm= 1260 - hcf
lcm= hcf+ 900
1260-hcf = hcf + 900
1260- 900= hcf + hcf
360 = 2× hcf
hcf= 360/2
hcf= 180
lcm = 180+ 900
lcm= 1080
product of 2 no. = lcm× hcf
= 1080×180
Answered by
0
HEY FRIEND HERE IS UR ANSWER ,
Given that the sum of HCF and LCM = 1260.
LCM + HCM = 1260 --------------------- (1)
Given that their LCM is 900 more than the HCF.
Let HCF = x. ------------ (2)
Then the LCM = 900 + x. ------------------- (3)
On solving (1),(2),(3).
1260 = x + (900 + x)
1260 = x + 900 + x
1260 = 2x + 900
1260 - 900 = 2x
360 = 2x
x = 360/2
x = 180.
Now, we got
HCF = 180.
Then, LCM = 900
= 900 + 180
= 1080.
We know that product of two numbers = HCF * LCM
= 180 * 1080
= 194400.
HOPE IT HELPS :)
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