If the sum of n terms of an A.P. is . Write its common difference.
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Answered by
0
Answer:
The common Difference is 6 .
Step-by-step explanation:
Given :
Sum of n terms = 3n² + 5n…….(1)
On putting n =1 in eq (1),
Sn = 3x1² + 5x1
S1 = 3 + 5
S1 = 8
Sum of first 1 terms (S1) = first term(a) = 8
On putting n = 2 in eq (1),
S2 = 3 x 2² + 5 x 2
S2 = 3 × 4 + 10
S2 = 12 + 10
S2 = 22
a2 = S2 - S1
[nth term of the A.P., an = Sn – S(n – 1)]
a2 = 22 - 8
a2 = 14
common difference , d = a2 - a1
d = 14 - 8
d = 6
Hence , the common Difference is 6 .
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Answered by
6
Hi there!
Let a and d be the first term and common difference.
Sum of n terms = 3n² + 5n (Given)
When n=1
Sn = 3x1² + 5x1
S1 = 3 + 5
S1 = 8
First term is 8 i.e (a=8)
When n = 2
S2 = 3 x 2² + 5 x 2
S2 = 3 × 4 + 10
S2 = 12 + 10
S2 = 22
a2 = S2 - S1
an = Sn – S(n – 1)
a2 = 22 - 8
a2 = 14
d= a2 - a1
d = 14 - 8
d = 6
Thankyou :)
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