if the sum of 'N' terms of an AP is 3n2-2n. find the nth term of that AP
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Sn = 3n²-2n
Sn-1 = 3(n-1)²- 2(n-1) == 3n²+3-6n-2n+2 = 3n²-8n+5
An = Sn - Sn-1 == 6n-5
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would be the correct answer
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