If the sum of n terms of an AP is 3n2 + 5n, then which of its term is 164?
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51
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Given
Sn=3n sq + 5n
Now Tn= Sn-Sn-1
= 3nsq +5n- 3(n-1)sq -5(n-1)
= 3(nsq - nsq -1 +2n)+5 (n-n+1)
= 6n -3 + 5
= 6n +2
Now given tn= 164
6n+2=164
6n= 162
n= 27 Ans
Hope it hells...
Given
Sn=3n sq + 5n
Now Tn= Sn-Sn-1
= 3nsq +5n- 3(n-1)sq -5(n-1)
= 3(nsq - nsq -1 +2n)+5 (n-n+1)
= 6n -3 + 5
= 6n +2
Now given tn= 164
6n+2=164
6n= 162
n= 27 Ans
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