if the sum of n terms of an arithmetic progression 6nsqure+6n , then the fourth term of the series
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0
Answer:
48
Step-by-step explanation:
sum of n terms is given by :
Tn = 6n² + 6n
Now,
S3 = 6×3² + 6×3 = 54+18 = 72
S4 = 6×4² + 6×4 = 96+24 = 120
So fourth term will be :
(Sum of 4 terms - sum of 3 terms)
= 120 - 72 = 48
Answered by GauthMath.
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