Question

If the sum of square of zeros of the polynomial 6x^2+x+k is 25/36 find the value of k.

Answer 1

Answer:  k = -2

Step-by-step explanation:  Let the roots be α and β.

α + β = -1/6

αβ = k/6

α² + β² = 25/36

(α + β)² - 2αβ = 25/36

(-1/6)² - 2(k/6) = 25/36

1 - 12k = 25

12k = -24

k = -2