Question

If the sum of the ages of a father and his son in years is 65 and twice the difference of their ages in years is 50, then the age of the father in year is??

Its urgent, please help...

Answer 1

Let the age of son be y

let the age of father be x

x+y=65

and twice the difference of their age is 50 yrs

2(x+y)=50

2x+2y=50

x+y=65......1

2x-2y=50.......2

by elemination method adding 1 and 2

2(x+y=65)+2x-2y=50

therefore,

2x+2y=130

2x-2y=50

4x+0=180

x=180÷4

x=45

x+45=65

Therefore, 20 is son sage and 45 is father age.