If the sum of the ages of a father and his son is 45 years and thrice the difference of their ages is the same as the sum of their ages find fathers age
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Let
Age of Father=x yrs
Age of Son=y yrs
SUM OF AGES =x+y=45....(eq1)
ATQ
3(x-y)=45
x-y=15...(eq2(
eq1-eq2
x+y=45
x-y=15
2y=20
y=10
Age of Son=10years
Age of Father=45-10=35years
Age of Father=x yrs
Age of Son=y yrs
SUM OF AGES =x+y=45....(eq1)
ATQ
3(x-y)=45
x-y=15...(eq2(
eq1-eq2
x+y=45
x-y=15
2y=20
y=10
Age of Son=10years
Age of Father=45-10=35years
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