Math, asked by grishmamody590, 1 year ago

If the sum of the areas of two squares is 468m square and the difference of their perimeters is 24m then find the measurements of their sides

Answers

Answered by jiya143

2

x+ x= 468
2x =468
238
238 -24
214 is one of the area of square another is 262
there perimeter is 6 of all side

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