If the sum of the circumference of two circle with radius r1 and r2 is equal to the circumference of a circle with radius R,then what is the relation between r1,r2 and R
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circumference of circles is same...
so,
2πr1=2πr2
given,
2πr1+2πr2=2πR
2π(r1+r2)=2πR
both sides 2πis cancelled
r1+r2=R
[r1+r2=R].......
This is the relation you wanted..
so,
2πr1=2πr2
given,
2πr1+2πr2=2πR
2π(r1+r2)=2πR
both sides 2πis cancelled
r1+r2=R
[r1+r2=R].......
This is the relation you wanted..
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