Question

if the sum of the digits of a two-digit number is 6 if the digit of the number are reversed the new number is decreased by 36 find the new number
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Answer 1

Answer:

Let the two digits of the number be 10s digit x and 1s digit y

Sum of the digits of a two-digit number is 6.

x + y = 6…Eq..1

If the digits are reversed, the number is decreased by 36.

The original number formed is 10x + y. On reversal of digits the number become 10y + x.

10x + y = (10y + x) + 36

10x + y = 10y + x + 36

10x - x + y - 10y = 36

9x - 9y = 36

9 (x - y) = 36

x - y = 36/9

x - y = 4

x = 4 + y…Eq..2

Now substituting the value of x from Eq..2 to Eq..1

x + y = 6

4 + y + y = 6

2y = 6 - 4

2y = 2

y = 1

The 1s digit is 1

To calculate value of x , now placing value of y in Eq…2

x = 4 + y

x = 4 + 1

x = 5

The 10s digit is 5 and the number is 51

Answer the number is 51

Step-by-step explanation:

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