if the sum of the first 14 term of an ap is 1050 and its first term is 10 find the 20th term
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sum of 14 terms=14/2(2a+(14-1)d)
1050=7(2a+13d)
150=20+13d
130=13d
d=10
nth term=a+(n-1)d
=10+190
=200
therefore the 20th term of the AP is 200
1050=7(2a+13d)
150=20+13d
130=13d
d=10
nth term=a+(n-1)d
=10+190
=200
therefore the 20th term of the AP is 200
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