If the sum of the first 15 terms of the series (3/4)³ + (1¹/₂)³ + (2¹/₄)³ + 3³ + (3³/₄)³ + ....... is equal to 225 k, then k is equal to :
(A) 108 (B) 27
(C) 54 (D) 9
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Answer:
K is 108.
Hope it's helpful.
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