If the sum of the first n terms of AP is 4n-n^2 find 10th term and nth term
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Let a is first term and d is common difference
2n (2a+(n−1)d)=4n−n2
an+ 2n(n−1)d=4n−n2
a=3andd=−2Sum of first 2 terms =4×2−2 2 =4
2 nd term =3+(2−1)×−2=1
3 rd term =3+(3−1)×−2=−1
10th term =3+(10−1)×−2=−15
nth term =3+(n−1)×−2=5−2n
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