If the sum of the first p terms of an AP is ap2 + bp find
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Hi,
Given that the sum of p terms of an AP is ap2 + bp .
Now, Put p = 1,2,3,......
S 1 = a(1)2 + b(1)
S1 = a + b = a 1
S2 = a(2)2 + b(2)
S2 = 4a + 2b
Now, S2 = a1 + a 2
4a + 2b = a + b + a 2
4a + 2b - a - b = a 2
3a + b = a 2
Common difference, d = a2 - a1
d = 3a + b - (a + b)
d = 3a + b - a - b
d = 2a
Therefore, the common difference of the given AP is 2a.
Hope this helps u..........
Given that the sum of p terms of an AP is ap2 + bp .
Now, Put p = 1,2,3,......
S 1 = a(1)2 + b(1)
S1 = a + b = a 1
S2 = a(2)2 + b(2)
S2 = 4a + 2b
Now, S2 = a1 + a 2
4a + 2b = a + b + a 2
4a + 2b - a - b = a 2
3a + b = a 2
Common difference, d = a2 - a1
d = 3a + b - (a + b)
d = 3a + b - a - b
d = 2a
Therefore, the common difference of the given AP is 2a.
Hope this helps u..........
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