If the sum of the natural number and its resiprocal is 13/6. find the number
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x+1/x=13/6
x square +1/x=13/6
6x square - 13x+6=0
6x square - 9x-4x+6=0
(3x-2) (2x-3)
x=2/3 (or) 3/2
x square +1/x=13/6
6x square - 13x+6=0
6x square - 9x-4x+6=0
(3x-2) (2x-3)
x=2/3 (or) 3/2
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