If the sum of the number and its reciprocal is equal to 10\3 find the cube of the number
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Answer:
3
Step-by-step explanation:
Let the number be x. Given sum of number and it's reciprocal is 103.
∴x+1x=103
∴3x2−10x+3=0
∴3x2−9x−x+3=0
∴(3x−1)(x−3)=0
∴x=3 or x=13
Thus the number is 3.
Short cut:
The sum is 103. So it's safe to say x would be a multiple of 3. Try all the possible values.
Here 3+13=103
Thus 3 is the required number.
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