Question

) If the sum of the of zeros of the polynomial 6x^2 +x+k is 22/36 find the value of k​

Answer 1

Answer:

Let's a and b the zeroes of the polynomial

= a² + b² = 25/36 ( given)

We have ( a+ b² ) = a² + b² + 2ab.

(1)

= a²+b²=(a+b )² - 2ab

We have a = -1/6 , ab = k/6

Substituting the above in ( 1 ) we get

( -1/6) - 2 x k/6 = 25/36

= 1/36 - 2k/6 = 25 /36

= 2k /6 = 25-1/36=24/36=4/6

= -2k = 4 or k = -2

Hope it will help you

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