If the sum of the parallel sides of trapezium is 20cm and its height is 7 cm
then the area of trapezium is __cm2.
Answers
Answer:
Area of trapezium=
2
1
×Sum of parallel sides×Distance between them.
Area of trapezium =
2
h
(a+b), where a and b are base and h is height.
Here, a=24 cm, b=20 cm and h=15 cm
Therefore, Area=
2
15
(24+20)=330cm
2
Given:
Area of the trapezium =91 cm
2
Height =7 cm
Let the length of the smaller side be x.
Then, the length of the longer side will be 8 more than the smaller side, i.e. 8+x.
Area of trapezium =
2
1
×(Sum of the parallel sides)×(Height)
⇒91=
2
1
×[(8+x)+x]×(7)
⇒91=
2
7
×[8+x+x]
⇒91×2=7×[8+2x]
⇒7×[8+2x]=182
⇒[8+2x]=
7
182
=26
⇒8+2x=26
⇒2x=26−8=18
⇒x=
2
18
=9 cm
∴ Length of the shorter side of the trapezium =9 cm
And, length of the longer side =8+x=8+9=17 cm
17+9=26 Answer
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