Question

If the sum of the roots of the quadratic equation 2x^2 + (2k-1)x (k-4)=0 is equal to the product of its roots, then the
value of k is
(a) -3
(b) 3
(d) 0
(c) 2​​

Answer 1

Answer:

(a) -3

Step-by-step explanation:

2x^2 + (2k-1)x - (k-4)=0

Sum of the roots =  Product of the roots: -b/a= c/a

-(2k-1)/2 = -(k-4)/2

-2k+1 = -k+4

-k=3

k=-3

Option (a) -3 is correct

Answer 2

Answer:

Step-by-step explanation:

let the roots be a and b

a+b=-(2k-1)/2

ab=(k-4)/2

both are equal

-2k+1/2=k-4/2

-2k+1=k-4

3k=5

k=5/3